The price of Mid-Range Hotel (Room/Night) in Cleveland, United States is 199.10 USD
Mid-Range Hotel in Cleveland, United States
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| Currency | Code | Symbol | Value |
|---|---|---|---|
| Czech Republic Koruna | CZK | Kč | 4,009.2966 CZK |
| CFA Franc BEAC | XAF | CFAF | 96,266.6419 XAF |
| Congolese Franc | CDF | Fr | 183,556.2630 CDF |
| Rwandan Franc | RWF | Fr | 133,989.9198 RWF |
| Ugandan Shilling | UGX | USh | 503,567.7020 UGX |
| Iraqi Dinar | IQD | ع.د | 231,722.5350 IQD |
| Other cities | Price | COMPARED WITH Cleveland |
|---|---|---|
| Zuni Pueblo | 181.00 USD | -9.09% |
| Zephyrhills | 181.00 USD | -9.09% |
| Zellwood | 170.14 USD | -14.55% |
| Zelienople | 166.52 USD | -16.36% |
| Zeeland | 181.00 USD | -9.09% |
| Zapata | 161.09 USD | -19.09% |
Mid-Range Hotel price comparison chart
The Mid-Range Hotel price comparison chart shows that price for Mid-Range Hotel (Room/Night) in Cleveland is % higher than the same Mid-Range Hotel price in , United States.